Assignment one

02_activities/assignments/Assignment1.md

@@ -104,7 +104,7 @@ Please do not pick the exact same tables that I have already diagrammed. For exa
 	- These are the tables that are connected
 	- <img src="./images/01_farmers_market_conceptual_model.png" width="600">
 - The column names can be found in a few spots (DB Schema window in the bottom right, the Database Structure tab in the main window by expanding each table entry, at the top of the Browse Data tab in the main window)
-
+![alt text](<Untitled Diagram.drawio.png>)
 ***
 
 ## Section 2:

02_activities/assignments/assignment1.sql

@@ -1,24 +1,34 @@
+
 /* ASSIGNMENT 1 */
 /* SECTION 2 */
 
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT *
+FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT *
+FROM customer
+ORDER BY customer_last_name ASC, customer_first_name ASC
+LIMIT 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+SELECT *
+FROM customer_purchases
+WHERE product_id = 4
+or product_id=9;
 
 -- option 2
-
+SELECT *
+FROM customer_purchases
+WHERE product_id IN (4,9);
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -27,30 +37,49 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+SELECT *, (quantity* cost_to_customer_per_qty) as price
+FROM customer_purchases
+WHERE vendor_id>=8
+AND vendor_id<=10;
 
 -- option 2
-
+SELECT *, (quantity* cost_to_customer_per_qty) as price
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10;
 
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT product_id,product_name
+,CASE WHEN product_qty_type= 'unit'
+      THEN 'unit'
+	  ELSE 'bulk'
+END as prod_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT product_id,product_name
+,CASE WHEN product_name like '%pepper%'
+      THEN 1
+	  ELSE 0
+END as pepper_flag
+FROM product;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+SELECT DISTINCT v.vendor_id,vendor_name,market_date
+FROM vendor as v
+INNER JOIN vendor_booth_assignments as vb
+on v.vendor_id
+ORDER By vendor_name,market_date;
 
 
 
@@ -59,15 +88,24 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT vendor_id, count(booth_number) as rented_booth
+FROM vendor_booth_assignments
+GROUP by vendor_id;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
-
+SELECT customer_first_name, customer_last_name, c.customer_id,
+       SUM(quantity * cost_to_customer_per_qty) AS total_spent
+FROM customer_purchases AS cp
+INNER JOIN customer AS c
+ON cp.customer_id = c.customer_id
+GROUP BY c.customer_id, customer_first_name, customer_last_name
+HAVING total_spent > 2000
+ORDER BY customer_last_name, customer_first_name;
 
 
 --Temp Table
@@ -82,19 +120,37 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+DROP TABLE if EXISTS new_vendor;
 
+CREATE TEMP TABLE new_vendor as 
+SELECT *
+FROM vendor;
+
+INSERT INTO new_vendor(vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Soperfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');
+
+SELECT *
+FROM new_vendor;
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
 
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
-
+SELECT customer_id,
+ strftime('%Y',market_date),
+ strftime('%m',market_date)
+FROM customer_purchases
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
 Remember that money spent is quantity*cost_to_customer_per_qty. 
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
-
+SELECT customer_id,
+    SUM(quantity * cost_to_customer_per_qty) AS total_spent
+FROM customer_purchases
+WHERE STRFTIME('%m', market_date) = '04'
+  AND STRFTIME('%Y', market_date) = '2022'
+GROUP BY customer_id;