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Binary file added 02_activities/assignments/ERDs.pdf
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61 changes: 55 additions & 6 deletions 02_activities/assignments/assignment1.sql
Original file line number Diff line number Diff line change
Expand Up @@ -5,21 +5,25 @@
--SELECT
/* 1. Write a query that returns everything in the customer table. */


select * from customer;

/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */

select * from customer
order by customer_last_name, customer_first_name
limit 10;


--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1

select * from customer_purchases where product_id = 4 or product_id = 9;

-- option 2


select * from customer_purchases where product_id in (4,9);

/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
filtered by vendor IDs between 8 and 10 (inclusive) using either:
Expand All @@ -28,30 +32,50 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
*/
-- option 1

select *, (quantity * cost_to_customer_per_qty) as price from customer_purchases
where vendor_id >= 8 and vendor_id <= 10;

-- option 2


select *, (quantity * cost_to_customer_per_qty) as price from customer_purchases
where vendor_id between 8 and 10;

--CASE
/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz.
Using the product table, write a query that outputs the product_id and product_name
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */


select product_id, product_name,
case
when product_qty_type = 'unit' then 'unit'
else 'bulk'
end as prod_qty_type_condensed
from product;

/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */

select product_id, product_name,
case
when product_qty_type = 'unit' then 'unit'
else 'bulk'
end as prod_qty_type_condensed,
case
when lower(product_name) LIKE '%pepper%' then 1
else 0
end as pepper_flag
from product;


--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */


select * from vendor v
inner join vendor_booth_assignments vba on v.vendor_id = vba.vendor_id
order by v.vendor_name, vba.market_date;


/* SECTION 3 */
Expand All @@ -60,6 +84,9 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */

select vendor_id, count(*) as booth_rental_count
from vendor_booth_assignments
group by vendor_id;


/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
Expand All @@ -68,6 +95,14 @@ of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

select c.customer_id, c.customer_first_name, c.customer_last_name,
sum(cp.quantity * cp.cost_to_customer_per_qty) as total_spent
from customer c
join customer_purchases cp
on c.customer_id = cp.customer_id
group by c.customer_id, c.customer_first_name, c.customer_last_name
having sum(cp.quantity * cp.cost_to_customer_per_qty) > 2000
order by c.customer_last_name, c.customer_first_name;


--Temp Table
Expand All @@ -82,6 +117,12 @@ When inserting the new vendor, you need to appropriately align the columns to be
VALUES(col1,col2,col3,col4,col5)
*/

create table temp.new_vendor as
select * from vendor;

insert into temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
values (10, 'Thomass Superfood Store', 'Fresh Focused store', 'Thomas', 'Rosenthal');



-- Date
Expand All @@ -90,11 +131,19 @@ VALUES(col1,col2,col3,col4,col5)
HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */


select customer_id,
strftime('%m', market_date) as month,
strftime('%Y', market_date) as year
from customer_purchases;

/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Remember that money spent is quantity*cost_to_customer_per_qty.

HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */

select customer_id, sum(quantity * cost_to_customer_per_qty) as total_spent
from customer_purchases
where strftime('%Y', market_date) = '2022'
and strftime('%m', market_date) = '04'
group by customer_id;
91 changes: 90 additions & 1 deletion 02_activities/assignments/assignment2.sql
Original file line number Diff line number Diff line change
Expand Up @@ -20,6 +20,13 @@ The `||` values concatenate the columns into strings.
Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed.
All the other rows will remain the same.) */

select * from product
where product_size is null or product_qty_type is null;

select product_name || ', ' ||
coalesce(product_size, '') || ' (' ||
coalesce(product_qty_type, 'unit') || ')' as formatted_product
from product;


--Windowed Functions
Expand All @@ -32,17 +39,37 @@ each new market date for each customer, or select only the unique market dates p
(without purchase details) and number those visits.
HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */

select customer_id, market_date,
row_number() over (
partition by customer_id
order by market_date
) as visit_number
from customer_purchases;


/* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1,
then write another query that uses this one as a subquery (or temp table) and filters the results to
only the customer’s most recent visit. */

select * from (
select customer_id, market_date,
row_number() over (
partition by customer_id
order by market_date desc
) AS visit_number
from customer_purchases
) as ranked_visits
where visit_number = 1;


/* 3. Using a COUNT() window function, include a value along with each row of the
customer_purchases table that indicates how many different times that customer has purchased that product_id. */

select customer_id, product_id, market_date, quantity, cost_to_customer_per_qty,
count(*) over (
partition by customer_id, product_id
) as times_purchased
from customer_purchases;


-- String manipulations
Expand All @@ -57,10 +84,18 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for

Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */

select product_id, product_name,
trim(substr(
product_name,
instr(product_name, '-') + 1
)) as description
from product;


/* 2. Filter the query to show any product_size value that contain a number with REGEXP. */

select product_id, product_name, product_size from product
where product_size regexp '[0-9]';


-- UNION
Expand All @@ -73,6 +108,26 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
3) Query the second temp table twice, once for the best day, once for the worst day,
with a UNION binding them. */

-- Get highest and lowest sales days
select market_date, total_sales from (
select
market_date,
SUM(quantity * cost_to_customer_per_qty) as total_sales
from customer_purchases
group by market_date
order by total_sales desc
limit 1
)
union
select market_date, total_sales from (
select
market_date,
SUM(quantity * cost_to_customer_per_qty) as total_sales
from customer_purchases
group by market_date
order by total_sales asc
limit 1
);



Expand All @@ -89,6 +144,13 @@ Think a bit about the row counts: how many distinct vendors, product names are t
How many customers are there (y).
Before your final group by you should have the product of those two queries (x*y). */

select v.vendor_name, p.product_name,
count(distinct c.customer_id) * 5 * vi.original_price as total_revenue
from vendor_inventory vi
cross join customer c
join vendor v on vi.vendor_id = v.vendor_id
join product p on vi.product_id = p.product_id
group by v.vendor_name, p.product_name, vi.original_price;


-- INSERT
Expand All @@ -97,18 +159,30 @@ This table will contain only products where the `product_qty_type = 'unit'`.
It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`.
Name the timestamp column `snapshot_timestamp`. */

-- Create the new table with the extra column
create table product_units as
select product_id, product_name, product_size, product_qty_type,
product_category_id, CURRENT_TIMESTAMP as snapshot_timestamp
from product
where product_qty_type = 'unit';


/*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp).
This can be any product you desire (e.g. add another record for Apple Pie). */

insert into product_units (
product_id, product_name, product_size, product_qty_type,
product_category_id, snapshot_timestamp
)
values (999, 'Apple Pie', '12"', '3', 'unit', CURRENT_TIMESTAMP);


-- DELETE
/* 1. Delete the older record for the whatever product you added.

HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/

delete from product_units
where product_name = 'apple pie' and snapshot_timestamp is null;


-- UPDATE
Expand All @@ -128,6 +202,21 @@ Finally, make sure you have a WHERE statement to update the right row,
you'll need to use product_units.product_id to refer to the correct row within the product_units table.
When you have all of these components, you can run the update statement. */

ALTER TABLE product_units
ADD current_quantity INT;


update product_units
set current_quantity = coalesce(
(select T1.quantity
from vendor_inventory as T1
where T1.product_id = product_units.product_id
and T1.market_date = (
select MAX(T2.market_date)
from vendor_inventory as T2
where T2.product_id = product_units.product_id
)
), 0
);