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11 changes: 10 additions & 1 deletion 02_activities/assignments/Assignment1.md
Original file line number Diff line number Diff line change
Expand Up @@ -106,6 +106,9 @@ Please do not pick the exact same tables that I have already diagrammed. For exa
- <img src="./images/01_farmers_market_conceptual_model.png" width="600">
- The column names can be found in a few spots (DB Schema window in the bottom right, the Database Structure tab in the main window by expanding each table entry, at the top of the Browse Data tab in the main window)

##### My Logical Data Model
<img src="assignment_one_logical_data_model.png" width="500">

***

## Section 2:
Expand Down Expand Up @@ -205,5 +208,11 @@ Consider, for example, concepts of fariness, inequality, social structures, marg


```
Your thoughts...
The assigned article discusses how databases that embed societal value systems and social constructs profoundly perpetuate inequality and marginalization.
For the example of Pakistan's NADRA system, we observe a reflection and reinforcement of hierarchical/patriarchal power dynamics, where a government-official
marriage between a man and a woman determines their children's access to essential services. In our daily lives, facial recognition technologies, trained on
deeply human-biased databases that are categorized inherently with deep, implicit biases, amplify societal discrimination of racialized individuals, and
this is further demonstrated through the use of these technologies in policing. In addition, an attempt to operationalize gender as a boolean, as Pakistan's
NADRA system has done until 2009 not only dismisses the existence of non-binary gender identities but also overlooks how gender is inherently a social
construct shaped by value systems that, in turn, lead to differential socialization.
```
92 changes: 80 additions & 12 deletions 02_activities/assignments/assignment1.sql
Original file line number Diff line number Diff line change
Expand Up @@ -4,21 +4,29 @@

--SELECT
/* 1. Write a query that returns everything in the customer table. */

SELECT * FROM customer;


/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */

SELECT *
FROM customer
ORDER BY customer_last_name ASC, customer_first_name
LIMIT 10;


--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1

SELECT *
FROM customer_purchases
WHERE product_id IN (4, 9);

-- option 2

SELECT *
FROM customer_purchases
WHERE product_id = 4
OR product_id = 9;


/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
Expand All @@ -27,29 +35,54 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
2. one condition using BETWEEN
*/
-- option 1

SELECT cp.*,
quantity*cost_to_customer_per_qty AS price
FROM customer_purchases AS cp
WHERE vendor_id > 7 AND vendor_id < 11;

-- option 2

SELECT cp.*,
quantity*cost_to_customer_per_qty AS price
FROM customer_purchases AS cp
WHERE vendor_id BETWEEN 8 AND 10;


--CASE
/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz.
Using the product table, write a query that outputs the product_id and product_name
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */

SELECT product_id, product_name
,CASE WHEN product_qty_type = "unit"
THEN "unit"
ELSE "bulk"
END AS prod_qty_type_condensed
FROM product;


/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */

SELECT product_id, product_name
,CASE WHEN product_qty_type = "unit"
THEN "unit"
ELSE "bulk"
END AS prod_qty_type_condensed
, CASE WHEN product_name LIKE "%pepper%"
THEN 1
ELSE 0
END AS pepper_flag
FROM product;


--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
SELECT *
FROM vendor_booth_assignments AS vba
INNER JOIN vendor AS v
ON vba.vendor_id = v.vendor_id
ORDER BY v.vendor_name ASC, vba.market_date;



Expand All @@ -59,15 +92,28 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
-- AGGREGATE
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */

SELECT
vendor_id
,count(booth_number)
FROM vendor_booth_assignments
GROUP BY vendor_id;


/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
of customers for them to give stickers to, sorted by last name, then first name.

HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */

SELECT
customer_first_name
,customer_last_name
,SUM(quantity*cost_to_customer_per_qty) as total_spending
FROM customer_purchases AS cp
INNER JOIN customer AS c
ON cp.customer_id = c.customer_id
GROUP BY cp.customer_id
HAVING total_spending > 2000
ORDER BY customer_last_name, customer_first_name;


--Temp Table
Expand All @@ -81,20 +127,42 @@ When inserting the new vendor, you need to appropriately align the columns to be
-> To insert the new row use VALUES, specifying the value you want for each column:
VALUES(col1,col2,col3,col4,col5)
*/
DROP TABLE IF EXISTS temp.new_vendor ;

--make the table
CREATE TEMP TABLE temp.new_vendor AS

--definition of the table
SELECT *
FROM vendor;

INSERT INTO temp.new_vendor
VALUES(10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');


-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.

HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */

SELECT
customer_id
,strftime('%m', market_date) as month
,strftime('%Y', market_date) as year
FROM customer_purchases;


/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Remember that money spent is quantity*cost_to_customer_per_qty.

HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */

SELECT
customer_id
,SUM(quantity*cost_to_customer_per_qty) as spending
,strftime('%m', market_date) as month
,strftime('%Y', market_date) as year
FROM customer_purchases
WHERE month = '04'
AND year = '2022'
GROUP BY customer_id;
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