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ryan-hamblin
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Sep 8, 2017
| // return true if num is even | ||
| // otherwise return false | ||
| // code here | ||
| return !(num % 2); |
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Interesting approach. I'd like to see your thoughts behind coming up with this solution? Was it trial and error? Just found out that num % 2 gives us zero which is an undefined value so you can turn it to it's opposite which is True? Interesting.
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Some experience in c++ makes me use the NOT operator naturally, and it worked the first time I put it in. Interesting I didn't really think about it being undefined, I thought of it as 0, which in my mind is false
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