assignment-one

02_activities/assignments/assignment1.sql

@@ -5,53 +5,62 @@
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
 
-
+Select * from customer;
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+Select * from customer  order by customer_last_name,customer_first_name limit 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
 
+select * from customer_purchases where product_id in (4,9) order by product_id;
 
--- option 2
 
+-- option 2
 
+Select * from customer_purchases where product_id=4 or product_id=9 order by product_id;
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
 filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	1.  two conditions using AND
 	2.  one condition using BETWEEN
 */
 -- option 1
+select  *,(quantity* cost_to_customer_per_qty) as price from customer_purchases where vendor_id>=8 and vendor_id<=10 order by vender id;
 
 
--- option 2
 
+-- option 2
+select  *,(quantity* cost_to_customer_per_qty) as price from customer_purchases where  vendor_id  between 8 and 10 order by vendor_id ;
 
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+Select product_id,product_name,
+             case  product_qty_type when 'unit' Then 'unit' else 'bulk' end prod_qty_type_condensed
+from product order by product_name;			 
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+Select product_id,product_name,
+             case  product_qty_type when 'unit' Then 'unit' else 'bulk' end prod_qty_type_condensed, 
+			 case  when UPPER(product_name) like '%PEPPER%' then  1 else 0  end  pepper_flag
+from product order by product_name;		
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
-
+select vendor.vendor_name,vendor.vendor_owner_first_name,vendor.vendor_owner_last_name,vendor.vendor_type,vendor_booth_assignments.market_date from vendor inner join vendor_booth_assignments on vendor.vendor_id=vendor_booth_assignments.vendor_id order by vendor_name,market_date
 
 
 /* SECTION 3 */
@@ -60,15 +69,22 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+Select vendor_id,count(vendor_id) from vendor_booth_assignments group by vendor_id;
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
-
+SELECT
+	customer.customer_first_name,customer.customer_last_name,sum(cost_to_customer_per_qty*quantity)
+FROM
+	customer
+INNER JOIN customer_purchases ON customer.customer_id = customer_purchases.customer_id
+GROUP BY
+customer.customer_id
+HAVING sum(cost_to_customer_per_qty*quantity) >2000;
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -82,19 +98,30 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+create table temp.new_vendor as  select * from vendor
+insert into new_vendor (vendor_id,vendor_name,vendor_type,vendor_owner_first_name,vendor_owner_last_name) values (10,"Thomass Superfood Store", "a Fresh Focused store", "Thomas","Rosenthal")
 
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
-
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
+Select customer_id,strftime('%m',customer_purchases.market_date),strftime('%Y' ,customer_purchases.market_date) from customer_purchases
 
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
 Remember that money spent is quantity*cost_to_customer_per_qty. 
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
+
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+
+SELECT
+	customer.customer_first_name,customer.customer_last_name,sum(cost_to_customer_per_qty*quantity)
+FROM
+	customer 
+INNER JOIN customer_purchases ON customer.customer_id = customer_purchases.customer_id  and strftime('%Y',customer_purchases.market_date)='2022' and strftime('%m',customer_purchases.market_date)='04'
+GROUP BY
+customer.customer_id