London_10-Saliha_Popal-JavaScript-Core-2-Coursework-Week1

[SalihaPopal]

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Your Details

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Homework Details

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• Week:

Notes

• What did you find easy?

• What did you find hard?

• What do you still not understand?

• Any other notes?

[jxz12]

for these two you should access the dog object by doing dog.name or dog.breed

[jxz12]

here you should use the alternate method of accessing object data, which would be capitalCities[myCountry]

[jxz12]

here you are expected to sort through this list of basketballTeam.topPlayers and then print each of the players on a new line. You can do that with array methods .sort() and .forEach()

[jxz12]

you can avoid repeating yourself here by moving these console.log and for loop into another function which takes a recipe as an argument. e.g. function logRecipe(recipe) { ... }

[jxz12]

there is no need to use return when using forEach because the return value is discarded anyway (see https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/forEach)

[jxz12]

good work!

[SalihaPopal]

I learned some new and interesting refactor methods.

[SalihaPopal]

.forEch() is also the best mothod.
recipe1.ingredients.forEach(ingredient) => {
console.log(ingredient);
}

[SalihaPopal]

Or we can write the code as following:
function createLookup(countryCurrencyCodes) {
let currencyCodeLookup = {};

for (let countryCurrencyCode of countryCurrencyCodes) {
let countryCode = countryCurrencyCode[0];
let currencyCode = countryCurrencyCode[1];
currencyCodeLookup[countryCode] = currencyCode;
};

return currencyCodeLookup;
}

[jxz12]

I think your original solution is better, but this other solution is also nice and clear.

[SalihaPopal]

const MENU = {
burger: 6.5,
falafel: 7.25,
};

let cashRegister = {
orderBurger: function(balance) {
let finalBalance = balance;
let isBalanceBigEnough = balance - MENU.burger >= 0;
if (isBalanceBigEnough) {
finalBalance = balance - MENU.burger;
}
return finalBalance;
},
orderFalafel: function(balance) {
let finalBalance = balance;
let isBalanceBigEnough = balance - MENU.falafel >= 0;
if (isBalanceBigEnough) {
finalBalance = balance - MENU.falafel;
}
return finalBalance;
},
};

[jxz12]

I like your original solution better here too