2154\. Keep Multiplying Found Values by Two

Easy

You are given an array of integers `nums`. You are also given an integer `original` which is the first number that needs to be searched for in `nums`.

You then do the following steps:

1.  If `original` is found in `nums`, **multiply** it by two (i.e., set `original = 2 * original`).
2.  Otherwise, **stop** the process.
3.  **Repeat** this process with the new number as long as you keep finding the number.

Return _the **final** value of_ `original`.

**Example 1:**

**Input:** nums = [5,3,6,1,12], original = 3

**Output:** 24

**Explanation:** 
- 3 is found in nums. 3 is multiplied by 2 to obtain 6. 

- 6 is found in nums. 6 is multiplied by 2 to obtain 12. 

- 12 is found in nums. 12 is multiplied by 2 to obtain 24. 

- 24 is not found in nums. 
Thus, 24 is returned. 

**Example 2:**

**Input:** nums = [2,7,9], original = 4

**Output:** 4

**Explanation:** 
- 4 is not found in nums. 

Thus, 4 is returned. 

**Constraints:**

*   `1 <= nums.length <= 1000`
*   `1 <= nums[i], original <= 1000`
