2011\. Final Value of Variable After Performing Operations

Easy

There is a programming language with only **four** operations and **one** variable `X`:

*   `++X` and `X++` **increments** the value of the variable `X` by `1`.
*   `--X` and `X--` **decrements** the value of the variable `X` by `1`.

Initially, the value of `X` is `0`.

Given an array of strings `operations` containing a list of operations, return _the **final** value of_ `X` _after performing all the operations_.

**Example 1:**

**Input:** operations = ["--X","X++","X++"]

**Output:** 1

**Explanation:** The operations are performed as follows:

Initially, X = 0.

--X: X is decremented by 1, X = 0 - 1 = -1.

X++: X is incremented by 1, X = -1 + 1 = 0.

X++: X is incremented by 1, X = 0 + 1 = 1.

**Example 2:**

**Input:** operations = ["++X","++X","X++"]

**Output:** 3

**Explanation:** The operations are performed as follows:

Initially, X = 0.

++X: X is incremented by 1, X = 0 + 1 = 1.

++X: X is incremented by 1, X = 1 + 1 = 2.

X++: X is incremented by 1, X = 2 + 1 = 3.

**Example 3:**

**Input:** operations = ["X++","++X","--X","X--"]

**Output:** 0

**Explanation:** The operations are performed as follows:

Initially, X = 0.

X++: X is incremented by 1, X = 0 + 1 = 1.

++X: X is incremented by 1, X = 1 + 1 = 2.

--X: X is decremented by 1, X = 2 - 1 = 1.

X--: X is decremented by 1, X = 1 - 1 = 0.

**Constraints:**

*   `1 <= operations.length <= 100`
*   `operations[i]` will be either `"++X"`, `"X++"`, `"--X"`, or `"X--"`.
