1480\. Running Sum of 1d Array

Easy

Given an array `nums`. We define a running sum of an array as `runningSum[i] = sum(nums[0]…nums[i])`.

Return the running sum of `nums`.

**Example 1:**

**Input:** nums = [1,2,3,4]

**Output:** [1,3,6,10]

**Explanation:** Running sum is obtained as follows: [1, 1+2, 1+2+3, 1+2+3+4].

**Example 2:**

**Input:** nums = [1,1,1,1,1]

**Output:** [1,2,3,4,5]

**Explanation:** Running sum is obtained as follows: [1, 1+1, 1+1+1, 1+1+1+1, 1+1+1+1+1].

**Example 3:**

**Input:** nums = [3,1,2,10,1]

**Output:** [3,4,6,16,17]

**Constraints:**

*   `1 <= nums.length <= 1000`
*   `-10^6 <= nums[i] <= 10^6`