[!] Failed to inject DLL, exit... 5 #2
Description
I met some stranger things
mysql code:
#!/usr/bin/python
Win32 DLL injector from Grey Hat Python
Minor formatting cleanups done...
import sys
from ctypes import *
print "DLL Injector implementation in Python"
print "Taken from Grey Hat Python"
'''
if (len(sys.argv) != 3):
print "Usage: %s " %(sys.argv[0])
print "Eg: %s 1111 C:\test\messagebox.dll" %(sys.argv[0])
sys.exit(0)
'''
PAGE_READWRITE = 0x04
PROCESS_ALL_ACCESS = ( 0x00F0000 | 0x00100000 | 0xFFF )
VIRTUAL_MEM = ( 0x1000 | 0x2000 )
kernel32 = windll.kernel32
#pid = sys.argv[1]
#dll_path = sys.argv[2]
pid = 2312
dll_path = "C:\Users\Administrator\Desktop\pyplugins\ZhudongFangyu\ImgWalk.dll"
dll_len = len(dll_path)
Get handle to process being injected...
h_process = kernel32.OpenProcess( PROCESS_ALL_ACCESS, False, int(pid) )
if not h_process:
print "[!] Couldn't get handle to PID: %s" %(pid)
print "[!] Are you sure %s is a valid PID?" %(pid)
sys.exit(0)
Allocate space for DLL path
arg_address = kernel32.VirtualAllocEx(h_process, 0, dll_len, VIRTUAL_MEM, PAGE_READWRITE)
print "arg_address: ", arg_address
Write DLL path to allocated space
written = c_int(0)
kernel32.WriteProcessMemory(h_process, arg_address, dll_path, dll_len, byref(written))
Resolve LoadLibraryA Address
h_kernel32 = kernel32.GetModuleHandleA("kernel32.dll")
h_loadlib = kernel32.GetProcAddress(h_kernel32, "LoadLibraryW")
print "LoadLibraryA: ", h_loadlib
Now we createRemoteThread with entrypoiny set to LoadLibraryA and pointer to DLL path as param
thread_id = c_ulong(0)
if not kernel32.CreateRemoteThread(h_process, None, 0, h_loadlib, arg_address, 0, byref(thread_id)):
print "[!] Failed to inject DLL, exit...", kernel32.GetLastError()
sys.exit(0)
print "[+] Remote Thread with ID 0x%08x created." %(thread_id.value)
when i run it, i get
DLL Injector implementation in Python
Taken from Grey Hat Python
arg_address: 49938432
LoadLibraryA: 1978878195
[!] Failed to inject DLL, exit... 5
i don't know what's wrong, can i get some tips？